C=100+5x+4x^2

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Solution for C=100+5x+4x^2 equation: 



=100+5C+4C^2

We move all terms to the left:

-(100+5C+4C^2)=0

We get rid of parentheses

-4C^2-5C-100=0

a = -4; b = -5; c = -100;
Δ = b2-4ac
Δ = -52-4·(-4)·(-100)
Δ = -1575
Delta is less than zero, so there is no solution for the equation

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